DATE_FORMAT(): This function formats a specified date as per the format specifier (%e for date, %c for month, %Y for year, and many more). If you enter a negative parameter, the system subtracts the specified days, months, or years. I used the following code: SELECT h. 000 which is the start of the. You may: count the number of 24h elapsed time: day+1 - day = 1 day = 24h. PostgreSQL. Usage Notes¶. 1970年1月1日から2037年12月31日までの入力日付を示す数値。. Dynamic views containing Date, Time, or DateTime fields must be wrapped with the appropriate meta-SQL. declare @EmployeeStartDate datetime='01-Sep-2013' declare @EmployeeEndDate datetime='15-Nov-2013' select DateDiff (mm,@EmployeeStartDate, DateAdd (mm, 1,@EmployeeEndDate)) If. The days are in two different, adjacent months, so the answer is 1 month difference. SELECT DATEADD ( year, DATEDIFF ( year, 0, GETDATE ()), 0 ) 這個 SQL 的技巧是先取得和 1900-01-01 - 也就是上面的 0 的意思，SQL Server 中的第零天 - 差幾年 (從 DATEDIFF 得到一個整數)，再用 DATEADD 加 0 來將整數再轉成日期的型態。. FromDate, r. The result only contains the year, month and day, not the time. Here's how it does this: First the DATE function creates the date, 5/1/2016. Syntax. enddate, e3. object_id ) AS nbr FROM sys. datediff isn't a function in Oracle. Interprets an INT64 expression as the number of days since 1970-01-01. To compare dates in SQL, the most common functions used are DATEDIFF, DATE_ADD, DATE_SUB, and NOW. sql. Justin, the example which you gave, if that is the scenario I want the output as 1. This is in the manual. For example, assume that you had two elements, FIRST_NAME and LAST_NAME to concatenate into a 30-character field. 0. from this previous question How to calculate age in T-SQL with years, months, and days you can do procedure like this. Start date will be equal to add_months(sysdate,-6) And . Month and day of the year don’t appear to be factored into the equation. The MONTHS_BETWEEN () function is used to get the number of months between dates (date1, date2). ) that are available and in this tutorial, we look at how to use the DATEADD function in SQL queries, stored procedures, T-SQL scripts,. DateDiff function and I think it may have a parameter for indicating "in months" . E. Gets the number of intervals between two DATE values. Using this, I can find the first day of any given month using, but just that month and it does not take into consideration whether it is a business day or not. If you omit fmt, then date is rounded to the. month). 2. This question is asked many times and one of the suggested queries to get months between 2 dates is not working. Add to or subtract from a date. January 30, 2004 - 7:26 pm UTC. select trunc (months_between (:end_date,. The DATEDIFF() function returns the difference between two dates. 00. We need to pad a zero for single-digit months. The date calculator calculates the difference between the 'Start Date' and 'End Date' and displays it in terms of the number of years, months, weeks and days between them. SYSDATE) and subtracting a date from a timestamp (e. The Days, Months, and Years parameters can be negative or positive. then just use it in the script eg. The system calculates the number of complete months between given dates. The difference between 1st March 2011 and 29th February 2012 is 0. Viewed 44k times 3 I've got 2 date columns in my table (start_date, end_date). Oracle equivalent to SQL Server/Sybase. How best can this be written? I need to use this in a where clause on DI Studio. DECLARE @yourDate DATE = '20160229' select DATEADD (MONTH, DATEDIFF (MONTH, -1, @yourDate)-1, -1) Just a note: this does remove any time portion in the input date, which may or may not be desired. The value returned is always of data type DATE, even if you specify a different datetime data type for date. startdate or. This conversion uses the NLS_DATE_FORMAT parameter to decide the format of the output string. DATEDIFF Examples Using All Options. 24 th is the day value in the given date. Getting the 1st day of the month is simpler: select dateadd (day,- (day (current_timestamp)-1),current_timestamp) From your reference point-in-time, subtract (in days), 1 less than the current day-of-the-month component. Note that SQL Server DATEDIFF(month, date2, date1) function does not return exactly the same result, and you have to use an user-defined function if you need to fully emulate the Oracle MONTHS_BETWEEN function (see. Modified 1 year, 3 months ago. SELECT * FROM TABLE_NAME WHERE DATEADD (DAY, -90, GETDATE ()) between txtFromDate and txtToDate. To create the rows, use the month generation technique above. 9. Access Function: DateDiff ("m",PAID_DATE,STATIC_DATE) AS Months_Between. Current Date/Time. It should have been DATEDIFF NOT DATEADD with respect to the WEEK parameter. If the endDate has a day part less than startDate, it will get pushed to the previous month, thus datediff will give the correct number of months. If within the same year, you can use Date. Date2Date. Table 9. 9. Factor by 24 to get hours, 24*60 to get minutes, 24*60*60 to get seconds (that's as small as dates go). last_day (feb) to last_day (mar) is also commonly accepted as a "month". Field or Control. - Find the “date_diff” in minutes and add it with the “date_diff” in hours and the “date_ diff” in days. But your query is giving the last date of previous month. You get the difference in days. date_from, evnt. you can check against last 90 days. Sure, the query depends on which database you’re using (Oracle, SQL Server, MySQL, etc). 2323 days) multiply by 24 = hours, another 60 = minutes, another 60 = seconds. Next to calculate a month of services in a company by a user we would use ‘m’ to calculate the difference value. Syntax¶ MONTHS. g. SELECT DATEDIFF (month, '2017/08/25', '2011/08/25') AS DateDiff; Edit the SQL Statement, and click "Run SQL" to see the result. The following query selects all rows with a. SELECT DATEDIFF(month, @origin, @timestamp) - CASE WHEN DATEADD( month, DATEDIFF(month, @origin, @timestamp), @origin) > @timestamp THEN 1 ELSE 0 END AS diff2; This expression returns 3, which is the number of whole months between the two inputs. DatePart. HQL Date format in Oracle / PostgreSQL: select TO_CHAR. To make it easier for now, business day is simply weekdays and does not consider public holiday. Follow answered Aug 3, 2011 at 18:51. select dateadd(ms,-3,DATEADD(mm, DATEDIFF(m,0,getdate() )+1, 0)) Last Day of Current YearRemarks. 850". To get the start and end dates of each month within a given range, when the value of the @StartDate parameter is not the first day of the month: The first option is to truncate the @StartDate parameter to the. Asked 7 years, 2 months ago. Consider SQL Server function to calculate the difference between 2 dates in months: SQL Server : -- Difference between Oct 02, 2011 and Jan 01, 2012 in months SELECT DATEDIFF ( month, '2011-10-02', '2012-01-01') ; -- Result: 3. Just divide the total by 7 to get the weeks and then calculate the remaining days. DATEADD(month, DATEDIFF(month, 0, getdate())+1, 0) returns the beginning of next month. SELECT DATE '0016-08-03' - DATE '2016-07-08' FROM dual;-- -730461. Add a. SQL Server ignores that this is just one day. If you enter a negative parameter, the system subtracts the specified days, months, or years. If you want to confirm, simply run this. 3. Expressions must contain a complete hint. 5 Answers Sorted by: 65 I'd use months_between, possibly combined with floor: select floor (months_between (date '2012-10-10', date '2011-10-10') /12) from dual;. This question was incorrectly asked. The Question asked for "6 months from the system date". S is milliseconds in one or up to six digits. Aug 17, 2021 at 11:13. If you need to calculate minutes or seconds, you simply multiply the result by a constant: (date2 - date1)*1440 -- number of minutes (date2 - date1)*86400 -- number of seconds. In Oracle SQL, I want to display the difference between two dates in the format 'x years y months z days'. PostgreSQL - Date Difference in Months. Use DATEADD (): where HireDate < dateadd (year, -3, GETDATE ()) DATEDIFF () does not do what you think it does. datediff isn't a function in Oracle. The first one involves getting the difference in days and then converting it to 'x year y month z days'. To calculate the number of days between date1 and date2, you can use either Day of. 2903225806 DATE_DIFF =. Here’s the syntax for the DATEADD function: DATEADD (interval, number, date); The interval. select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. 1. Any help would be appreciated. public static int MonthDiff (DateTime d1, DateTime d2) { int retVal = 0; // Calculate the number of years represented and multiply by 12 // Substract the month number from the total // Substract the difference of the second month and 12 from the total retVal. Conversion among time units is also allowed; you can add, subtract, or compare dates by using days and state. 3. The resulting column will be in INTERVAL DAY TO SECOND. e. Instead of: datediff ('QUARTER', pr. A) Get the difference in months of dates on the same day. If date1 is earlier than date2, then the result is negative. 8. This function adds N months to a date and returns the same day N month after. Run SQL ». You can't transform this value to date by to_date function. 2. January 30, 2004 - 7:26 pm UTC. date_from) = 1. 1. . adddate addtime curdate current_date current_time current_timestamp curtime date datediff date_add date_format date_sub day dayname dayofmonth dayofweek dayofyear extract from_days hour last_day localtime localtimestamp makedate maketime. startdate, DATEDIFF(DAY,e1. Improve this answer. To get the months or years separately, use extract. txt","path":"inst/csv/jarChecksum. then the following should be the result. If you need to calculate minutes or seconds, you simply multiply the result by a constant: (date2 - date1)*1440 -- number of minutes (date2 - date1)*86400 -- number of seconds. Since you asked for days, I'll leave it to you to truncate this to 37 days or round it to 38. DATEADD () Adds or subtracts a specified time interval from a specified date. This is because the two dates are exactly 24 hours apart. 1. Function. When the reporting date month is the same as the target month you can get a round up To get the number of month or day, you change the first argument to month or day as shown below: Notice that the DATEDIFF () function takes the leap year into account. AccountNumber AND T2. If you subtract from one date other you will get a count of days between this two dates. There are two methods to achieve this. The DATEPART() function returns an integer which is a part of a date such as a day, month, and year. Examples of Results in Months. inner select select DATEDIFF(MONTH, 0, GETDATE()) will give the number of months from 1900-01-01 here it is 1350. DATEDIFF (MONTH, DATEADD (DAY,-DAY (startDate)+1,startDate),DATEADD (DAY,-DAY (startDate)+1,endDate)) Share. subtract and give the difference in number of months. It would need to be EndDate + 23:59:59. 天：. e. See Date and Time Data Types and Functions (Transact-SQL) for an overview of all Transact. mysql> SELECT something FROM tbl_name-> WHERE DATE_SUB(CURDATE(),INTERVAL 30 DAY) <= date_col; The query also selects rows with dates that lie in the future. Last 3 Months. Viewed 110k times 49 I have a table with following structure. buf 1 declare 2 total_days integer; 3 total_weeks integer; 4 remaining_days integer; 5 begin 6 total_days := date '2014-12-16' - date '2014-12-01'; 7. FLOOR (DATEDIFF (DAY, date_of_birth, reference_date) / 365. I suggest to use "months_between" function because it takes leap years into account (months_between wants 2 dates as parameters):. Notice that the first row has a difference of 1. If you want to format it as you wanted (note that mm format mask is for months; mi is for minutes), then you could do some extracting - again from timestamp (won't work for date):. Table 7-13 Date Format Models for the ROUND and TRUNC Date Functions. If date1 is later than date2 , then the result is positive. . Using datediff in oracle. If date1 is earlier than date2 , then the result is negative. Syntax %DateAdd(date_from, add_days) Description. If the year diff has to be counted this way then use: EXTRACT (YEAR FROM date_to) - EXTRACT (YEAR FROM date_from) Just for the log. For example, suppose you have values below the start and end times. Then use these rules to set the column values: Start date: for the first row, return the input date; otherwise return the first of the month; End date: get the month start for the next row and subtract one day from it. it returns the difference in days if datepart is day. There are two methods to achieve this. Sum (r => EF. This function helps to retrieve any particular value of the timestamp in any format that we wish. Justin, the example which you gave, if that is the scenario I want the output as 1. Also I am not sure about Oracle, mysql,. + (Concatenation) operator. This command prints the order date in the specified format. CREATE OR REPLACE FUNCTION datediff (p_what IN VARCHAR2, p_d1 IN DATE, p_d2 IN DATE) RETURN NUMBER /* Updated to reflect current database and PL/SQL. Now I see two ways to achieve this: The MONTHS_BETWEEN () function is used to get the number of months between dates (date1, date2). g. See the following conditions: If date1 is later than date2, then the result is positive. As such, the use, reproduction, duplication, release, display, disclosure, modification, preparation of derivative works, and/or adaptation of i) Oracle programs (including any operating system, integrated software, any programs embedded, installed, or activated on delivered hardware, and modifications of such programs), ii) Oracle computer. This function is used to get the timestamp value from the specified character string. DiffYears Returns the difference in years between two dates. Option 1. Oracle Fusion Application Toolkit Cloud Service - Version 11. 0 and later Information in this document applies to any platform. 0. Here is an example that uses date functions. Using the standard EMP and DEPT tables, for example. I) if you need to calculate the elapsed time in seconds between two timestamp columns try this: SELECT extract ( day from (end_timestamp - start_timestamp) )*86400 + extract ( hour from (end_timestamp - start_timestamp) )*3600 + extract ( minute from (end_timestamp - start_timestamp) )*60 + extract ( second from (end_timestamp - start. Then you'll see the number. select S. Functions, you can call DateDiffDay: var ans = from t in Table1 group t by 1 into tg select tg. Currently, my code just returns zero on the right side of the decimal place. 2258064516 DATE_DIFF = 1. 1. You can even find the number of hours, minutes, seconds, and so on in terms of details in. 005479 0. , for the Oracle database: sale_date >= TRUNC (sysdate) AND sale_date < TRUNC (sysdate + INTERVAL '1' DAY) Another common obfuscation is to compare dates as strings as shown in the following PostgreSQL example:The trick here is to get the first day of the next month which will always be 01-NextMonth-Year. The return type is always DATE, regardless of the datatype of date. The months_between function returns the elapsed months going from the second date to the first. {"payload":{"allShortcutsEnabled":false,"fileTree":{"inst/csv":{"items":[{"name":"jarChecksum. You can use this to fetch all the days between two dates by: Subtracting the first date from the last to get the number of days. 58064516129032. 000000 1. 10. SELECT DATEADD (month, 1, '20220730'); The below DATEADD will add 1 year to the provided date value, the year changed from 2022 to 2023. I have a table where PurchasedDate is maintained. In addition, with DATEDIFF () the column is an argument to the function. This is not permitted when the subquery follows =, !=, <, <= , >, >= or when the. g for me the max dates is 1399, You can calculate this with select count(*) from sys. 005479 (1 year + 2/365 years). I see that marked final solution is not correct always. The desired output is: CustName Year OrderDate AA 2000 01-JAN-2000 AA 2000 05-FEB-2000 AA 2000 10-MAR-2000 AA 2007 05-MAY-2007 AA 2007 07-JUN-2007 AA 2007 06-JUL-2007. Specifically, it gets the difference between 2 dates with the results returned in date units specified as years, months days, minutes, seconds as a bigint value. The easiest is the connect by level method: Copy code snippet. I've tried Datediff(day, start_date, end_date), but I was prompt with: invalid column name. month: Number - The month (0-11) where 0 is January and 11 is December. = Duration. DATEENTERED ,* from sometable S where S. DATEADD (mm, 1, @Date) and subtract 1 day from it to get the last day of current month. Here is an example that uses date functions. Its seems that "DATEADD ": invalid identifier. Tip 032: Summary of Date Functions. 2 Answers Sorted by: 0 The best thing to do in this case is to use Oracle's MONTHS_BETWEEN () function. So, there’s. We will be using the same employees table in order to demonstrate the intricacies of calculating the difference between two dates in terms of weeks, months, or years using MySQL’s DATEDIFF() function. T was trying do calculate age as on todays date in ORACLE but after a lot of brain storming i didn't get it. Month difference between two dates in sql server. Admission_Date) > 5. Improve this answer. Join our newsletter and get access to exclusive content every month. SELECT DATEADD(s,0,DATEADD(mm, DATEDIFF(m,0,getdate()),0))Time Calculator. Our SQL tutorial will teach you how to use SQL in: MySQL, SQL Server, MS Access, Oracle, Sybase, Informix, Postgres, and other database systems. date_open END. 3. This gets the year difference between the birth date and the current date. ORA-00937 when calculating a sub-value in an aggregate select statement. The weekday (dw) datepart returns a number that. Quarter (rounds up on the sixteenth day of the second month of the quarter) Same day of the week as the first day of the calendar week as defined by the ISO 8601 standard, which is Monday. QlikView date and time functions are used to transform and convert date and time values. It’s a seven byte store of century, year, month, day and hour, minute and second. The recommended solution on Stack Overflow for example is this. But if you don't want the year, then just adjust the 'MM/yyyy' part to suit. Modified 2 years, 9 months ago. 'month' or month). 0: EF. Improve this answer. The starting day of the week used by the format models DAY, DY, and D is specified. So if there are two dates separated by one day, the year difference can be 1 (see select datediff (year, '20141231', '20150101') ). The next example will show the differences between two dates for each specific datapart and abbreviation. DATEDIFF() Returns the difference between the two dates. CASE WHEN a. DATE_DIFF = 1. select DATEADD(MONTH,1350,0) will give 2012-07-01 00:00:00. Share. Functions are based on a date-time serial number that equals the number of days since December 30, 1899. I recommend you have a stab yourself. You can even find the number of hours, minutes, seconds, and so on in terms of details in between the two. startdate: The first date or datetime value. 2 -Increment by 1 into total months count -. All functions can be used in both the load script and in chart expressions. The table contains the data about each staff member’s employment date. Functions. date. select. Converts one date format to a new format and returns the result. Then, it converts that result to a date, using the format 'yyyy-MM-dd'. The minus sign is used to compute the difference between two. In this tutorial, you have learned how to use the Oracle INTERVAL data type to store periods of time in the tables. 6222691' DECLARE @date2 datetime2 = '2022-01-14 12:32:07. If you are comparing to a date column in a existing table, then you need the date part too as you want to know December of which year was the previous month. ArrivalDate, Trips. select datediff (q,'03-30-2005','04-01-2005') will return 1. How can I calculate the date difference between these 2 columns? sql; sql-server-2008; t-sql; datediff. I want to calculate the current Age from Date of Birth in my Oracle function. Before using this function, you must set the NLS_DATE_FORMAT parameter to display 24-hour time. The dateadd function adds or subtracts a number of specified time units from a given date. JohnD JohnD. The default is date format 1. Hi tom, I want day, month, minute and years difference everyting in seconds. For example, the function considers each of the following pairs of dates/timestamps to be exactly 1. And then we need to convert the output of DATEPART to a 2-digit month number. I have to get the date from the system and calculate the date difference in days. Thanks in advance for any help; this has been driving us crazy for a few months now. If date1 is later than date2, then the result is positive. One option that avoids needing to add EndDate + 23:59:59. NET SQL Added in; EF. Accountnumber = T1. members, Datediff( GetFirstDate([Time dimension]. Do this even for a single day—e. , SYSDATE - pr. NEXT_QUARTERDECLARE @gapPeriod DATETIME = DATEADD(MONTH,-2,GETDATE()); --Period:Last 2 months. answered Oct 19, 2016 at 9:38. Java date functions. DP_MONTH returns the distance between the months capturing the input dates. So then in DATEADD(month, DATEDIFF(month, 0, GETDATE()), 0) that same number of months is added back to 1900-01-01 to get the start of the current month. @KanagaveluSugumar - An Oracle DATE always has a year, month, day, hour, minute, and second component. That prevents. The days are in two different, adjacent months, so the answer is 1 month difference. Also, you can check this for minutes : Oracle : how to subtract two dates and get minutes of the result. DATE_FROM_UNIX_DATE. 15 between 2 values that are 1 year, 1 month and 15 days apart. g. i need to find the difference of two dates as the number of months: find the last day of the month of both the dates. If you want an integer number of days. If IsDate (startdate) and IsDate (enddate) Then. Oracle Database enables you to perform arithmetic operations on dates and time stamps in several ways: Add a numeric value to or subtract it from a date, as in SYSDATE + 7; Oracle Database treats the number as the number of days. 取得一季中的第一天：. Then loop over the last few days to get the result. Taking out our calculator, we see that 30 minutes equals 1day/24hours*0. Subtracting two dates will return if and only if they are the same year, the same month, the same day, the same hour, the same minute, and the same second. SELECT DATEDIFF (second, '2019-12-31 23:59:59', '2020-01-01 00:00:00'); A value of 1 is returned because the boundary of seconds is crossed once. 3 Answers. Select name,surname,datediff(YY,birthDate,getdate()) as age from students order by age. 997 to avoid that. g. If this solve your problem, here's the sql server syntax, just replace the variable @yourDate with your column name. I usually used MySQL or sometimes Oracle but now I have to switch to Teradata. Select DATEDIFF (MM,0,GETDATE ()) Output - 1374, If getdate () output is "2014-07-23 19:33:46. For example, you could use the DATEDIFF function in VBA code and create the following function: Function TestDates (pDate1 as Date, pDate2 as Date) as Long TestDates = DateDiff ("d", pDate1, pDate2) End Function. The math is 100% accurate for dates within a couple of hundred years or so. So, this expression converts SYSDATE to a string, using whatever local settings are on your system. AgeInYears value of 0 while in the other case the AgeInYears value is 1. Possible values: text representing an entry in the IANA time zone database. 1. (CASE WHEN Trips. ) and the. Syntax: TIMESTAMPADD (interval, expr, timestamp) Example:. This requires breaking the date into its year, month, and day parts, putting them together in "yyyy/mm/dd" format, then casting that back to a date. The difference between two dates (in oracle's usual database product) is in days (which can have fractional parts). g. DateGroup. The part can be the day of the date, month of the date, year of the date etc. By adding 1 month, I am calculating the first day of next month and then subtraction 3 milliseconds, which allows me to arrive at the last day of the current month. select (sysdate +1 - rownum) dt from dual connect by rownum <= (sysdate - add_months (sysdate - extract (day from sysdate),-2)); The "-2" is the number of prior full months of dates to include. What's the function in Oracle that would be the equivalent to DATEDIFF in the SQL Server? On Oracle, it is an arithmetic issue: Select DATE1. (date1 - date2)The TRUNC (date) function returns date with the time portion of the day truncated to the unit specified by the format model fmt. 365 / 365. 1. SELECT case when DATEDIFF(month, '2005-12-31' , '2006-04-01 ') > 3 then 'yes' else 'no' end Hope that helps, John. Syntax. Difference of two dates in months. Date3(year, month, day) – similar to the ‘Date’ function described above, except that the three parameters are passed in as separate year, month and day values. declare @datetime datetime; set @datetime = getdate (); select @datetime; select dateadd (year,datediff (year,0,@datetime),0); select dateadd (month,datediff (month,0,@datetime),0); select dateadd (day,datediff. startdate)-1 as [Datediff] from #temp e1 join #temp e3. 14. SQL> select 24 * (to_date ('2009-07-07 22:00', 'YYYY-MM-DD hh24:mi') - to_date ('2009-07-07 19:30', 'YYYY-MM-DD hh24:mi')) diff_hours from dual; DIFF_HOURS ---------- 2. Simply i need to convert this: SELECT FLOOR(DATEDIFF(NOW(),`startdate`)/365. g. months_between/120 = decades_between. The system calculates the number of complete months between given dates. select emplid from. ReturnDate)) + ' days') ELSE CAST(DATEDIFF(day, Trips. CODE = 'CONTACT_CLIENT' THEN a. SQL - two months from todays date in Oracle. Summary: in this tutorial, you will learn how to use the SQL DATEPART () function to return a specified part of a date such year, month, and day from a given date. DAYS function. We will be using the same employees table in order to demonstrate the intricacies of calculating the difference between two dates in terms of weeks, months, or years using MySQL’s DATEDIFF() function. Viewed 3k times 0 I have a table with a date column (DD/MM/YYYY hh:mm:ss) as follows:. EOMONTH (date [,months to add) Returns the last do of the month with an optional parameter to add months (+ or -). 0. from a date time value. 7 Date and Time Functions. Teams. In SQL Server, there is a function datediff with datepart 'q'/quarter which behaves as follows :--. 3. – WAMLeslie. Oracle equivalent to SQL Server/Sybase DateDiff. Oracle 9i and later versions support CURRENT_DATE and CURRENT_TIMESTAMP. The MONTHS_BETWEEN function returns an estimate of the number of months between two arguments. 在本文中，我们介绍了oracle数据库中的datediff函数。通过指定日期部分、开始日期和结束日期，我们可以使用datediff函数计算两个日期之间的差异。这对于计算日期之间的天数、小时数、分钟数等非常有用。希望本文对您理解datediff函数的使用有所帮助。 MySQL DATEDIFF: Calculating weeks, months, or years between two dates. The following illustrates the syntax of the DATEPART. In Oracle SQL, I want to display the difference between two dates in the format 'x years y months z days'. 1. 32 illustrates the behaviors of the basic arithmetic operators ( +, *, etc. Syntax. It counts the number of year boundaries between two dates. date_open are both of type date, you can simply subtract them to get a difference in days. DATEDIFF(interval, date1, date2) Parameter Values. Calculates the difference in week numbers and year numbers, subtracts the week numbers and then multiplies the result by 2 to calculate number of non-workdays between the two dates. In PostgreSQL there are basically 2 functions to do the same, as we have both date_part and extract: SELECT current_date AS ACTUAL_DATE, EXTRACT (DAY FROM current_date) AS ACTUAL_DAY, EXTRACT (MONTH FROM current_date) AS ACTUAL_MONTH, EXTRACT (YEAR FROM current_date) AS ACTUAL_YEAR. So far I have this: SELECT evnt.